DIV CSS 佈局教程網

 DIV+CSS佈局教程網 >> 網頁腳本 >> JavaScript入門知識 >> AJAX入門 >> AJAX詳解 >> sicp習題試解 (1.8)
sicp習題試解 (1.8)
編輯:AJAX詳解     
; ======================================================================
;
;          Structure and Interpretation of Computer Programs
;                  (trial answer to excercises)
;
;                 計算機程序的構造和解釋(習題試解)
;
;                                             created: code17 02/24/05
;                                             modifIEd:
; (保持內容完整不變前提下,可以任意轉載)
; ======================================================================

;; SICP No.1.8

;; 只需要替換No.1.7中的improve函數算法即可
(define (improve guess x)
  (/ (+ (/ x
           (* guess guess))
        (* 2 guess))
     3))
(define (good-enough? oldguess guess)
  (< (abs (/ (- guess oldguess)
             guess))
     0.001))
(define (cube-iter oldguess guess x)
  (if (good-enough? oldguess guess)
      guess
      (cube-iter guess
                 (improve guess x)
                 x)))
(define (cube-root x)
  (cube-iter 0.0 1.0 x))


;; Test-it:
;; Welcome to MzScheme version 209, Copyright (c) 2004 PLT Scheme, Inc.
;; > (cube-root 0)
;; 4.9406564584125e-324
;; > (cube-root 125)
;; 5.000000000287929
;; > (cube-root 1000)
;; 10.000000145265767
;; > (cube-root -27)
;; -3.000000005383821
;; > 
XML學習教程| jQuery入門知識| AJAX入門| Dreamweaver教程| Fireworks入門知識| SEO技巧| SEO優化集錦|
Copyright © DIV+CSS佈局教程網 All Rights Reserved